Question

f x+y=4 and xy=6,find the value of x^2+y^2.

kindly tell.

Answer 1

Answer:

24

Step-by-step explanation:

given :- x+y = 4

xy = 6

to find :- x^2+y^2

solution :- x+y=4

squaring both sides

(x+y)^2 = 6^2

x^2+y^2 + 2xy = 36

x^2+y^2+2×6= 36

x^2+y^2+12=36

x^2+y^2=36-12

x^2+y^2= 24

Answer 2

Step-by-step explanation:

(2x+y)

2

=(2x)

2

+y

2

+2×2x×y

⇒(2x+y)

2

=(4x

2

+y

2

)+4xy

⇒(2x+y)

2

=40+4×6⇒(2x+y)

2

=64

⇒2x+y=±

64

⇒2x+y=±8