F(x+y)=f(x)+f(y) then f is even function or odd function
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f(x)=kx & f(y) = ky
f(x+y) = f(x)+f(y) =k(x+y)
thus f is odd function
f(x+y) = f(x)+f(y) =k(x+y)
thus f is odd function
PatelRitnesh:
respond please, it is true or not.
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