f:{(x,y):x is wife of y}
A={all human beings in a city}
check if reflexive transitive or symmetric
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Answered by
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it is not reflexive as x cant be a wife of x
it is not symmetric because if x is wife of y then y is not wife of x
it is transitive as - x is the wife of y , so y is male n cant be a wife to any random z. there is no point in checking further if x can be wife of z or not. hence it is transitive but not reflexive or symmetric.
it is not symmetric because if x is wife of y then y is not wife of x
it is transitive as - x is the wife of y , so y is male n cant be a wife to any random z. there is no point in checking further if x can be wife of z or not. hence it is transitive but not reflexive or symmetric.
Answered by
1
For reflexive
(a,a)∈F
It is not reflexive because (a,a)∉F because a cannot be wife of a
For symmetric
(a,b)∈f then (b,a) should ∈f
It is not transitive because if (a,b)∈f means a is wife of b ,but for transitive (b,a) should belongs to f which is not possible b cannot be wife of a
For transitive
(a,b)∈f,(b,c)∈f
It is not symmetric because if (a,b)∈f means a is wife of b then (b,c)∉f because a is female which cannot comes as male.according to situation.
(a,a)∈F
It is not reflexive because (a,a)∉F because a cannot be wife of a
For symmetric
(a,b)∈f then (b,a) should ∈f
It is not transitive because if (a,b)∈f means a is wife of b ,but for transitive (b,a) should belongs to f which is not possible b cannot be wife of a
For transitive
(a,b)∈f,(b,c)∈f
It is not symmetric because if (a,b)∈f means a is wife of b then (b,c)∉f because a is female which cannot comes as male.according to situation.
namku:
this is wrong. the function is transitive. i think ur concept of transitivity is not clear
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