Question

f(x y)=x²y²-5x²-8xy-5y² at (0,0) is​

Answer 1

Answer:

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Step-by-step explanation:

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Answer 2

Given:

The function f(x y)=x²y²-5x²-8xy-5y²

To find:

Value of  f(x y) at point (0, 0)

Solution:

We have given,

f(x y)=x²y²-5x²-8xy-5y²

We have find value of function at x = 0 and y =0

So, put value of x and y in equation

f(0, 0)=(0)²(0)²-5(0)²-8(0)(0) -5(0)²

         = 0

Hence the value of (x y)=x²y²-5x²-8xy-5y² at (0,0) is​ 0.