Question

F(x) y³-y²-y-1 find f(y+1)

Answer 1

Answer:

I hope you anderstand sir

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Answer 2

$\mathfrak{dear\;user }$

$\mathfrak{question-}F(x) y^3-y^2-y-1 find f(y+1)$

$\mathfrak{here\:is\:the\:solution\:for \:the question }$

Given :

$f(y) = y^{3} - y^{2} - y - 1$

To find :

$f(y + 1)$

$f(y) = y^{3} - y^{2} - y - 1$

$f(y) = y^{2} ( y - 1) - ( y + 1)$

Now,

$f(y +1) = (y + 1)^{2} ( y + 1 - 1) - ( y + 1 +1)$

$f(y +1) = y ( y + 1)^2 - ( y + 2)$

$f(y +1) = y ( y^{2} + 1 + 2y) - y - 2$

$f(y +1) = y^{3} + y + 2y^{2} - y - 2$

$f(y +1) = y^{3} +2y^{2} - 2$

$Therefore, If f(y) =y^{3} - y^{2} - y - 1 then, f(y+1) = y^{3}+ 2y^{2} - 2$

(OR)

Given,

$f(x) =y^{3} - y^{2} - y - 1$

Since y is a constant with respect to x here,

$f(x) = c = y^{3} - y^{2} - y - 1$

$Now, f(y + 1) = c = y^{3} -y^{2} - y - 1x^{2}$

$\mathcal{MY\:EXPECTATION\: FOR \:THIS \: ANSWER \:IS }10\:thanks\:and \:brainlist$

$\mathcal{BY \:ROSHAN\: A \:USER \: OF \: BRAINLY}$

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