f(x2)=x3 then find f'(x)
Answers
Answered by
3
given,
f(x²)=x³
→let y =x²
x=√y
then f(y)=(√y)³
f(y)=y^(3/2)
then f(x)=x^3/2
f'(x) =3/2 x^1/2
I hope this will help u
f(x²)=x³
→let y =x²
x=√y
then f(y)=(√y)³
f(y)=y^(3/2)
then f(x)=x^3/2
f'(x) =3/2 x^1/2
I hope this will help u
dhathri123:
:)
plz watch this too https://brainly.in/question/1190733
i use app
its ok..is that question asked by u ?
ys
ok i will try
i am sorry..i dont know that concept still
ok....no problem
thanks for trying
:)
Answered by
1
f(x²)=x³ let y =x²
x=√y
then f(y)=(√y)³
f(y)=y^(3/2) then f(x)=x^3/2 now differentate with respect to
f'(x) =3/2*x^(3/2-1) =>f'(x) =3/2* x^1/2
x=√y
then f(y)=(√y)³
f(y)=y^(3/2) then f(x)=x^3/2 now differentate with respect to
f'(x) =3/2*x^(3/2-1) =>f'(x) =3/2* x^1/2
Similar questions