Question

f(x2)=x3 then find f'(x)

Answer 1

given,

f(x²)=x³

→let y =x²

x=√y

then f(y)=(√y)³

f(y)=y^(3/2)

then f(x)=x^3/2

f'(x) =3/2 x^1/2


I hope this will help u

Answer 2

f(x²)=x³ let y =x²
x=√y
then f(y)=(√y)³
f(y)=y^(3/2) then f(x)=x^3/2 now differentate with respect to
f'(x) =3/2*x^(3/2-1) =>f'(x) =3/2* x^1/2