Question

f(y)=6y-3y^2+3 find the value of polynomial y=1​

Answer 1

Step-by-step explanation:

RHS=6×1-3×1^2+3

RHS=6

LHS=f(y)=f×1=f

therefore f=6

Answer 2

Answer:

The value of the polynomial at $y=1$ is 6.

Step-by-step explanation:

In context to the question asked,

We have to find the value of the polynomial at $y=1$,

As per data given in the question,

The given polynomial,

$P(y)=6y-3y^2+3$

Now, by plugging the value of y as 1:

=> $P(y)=6y-3y^2+3$

=> $P(1)=6(1)-3(1)^2+3$

Simplifying it further, we get

=> 6 - 3 + 3

=> 6

Hence, the value of the polynomial at $y=1$ is 6.