Question

F1 =10 N and F2 = 20 N...find F2-F1 and tan alpha

Answer 1

Explanation:

F1 =10N and F2=20N angle is 60°

Resultant = √F₁² + F₂² + 2F₁ F₂Cos60°

=> Resultant  = √10² + 20² + 2*10*20(1/2)

=> Resultant  = √100 + 400 + 200

=> Resultant  = √700

= Resultant = 10√7

F1 =10N = 10i

F2=20N  =>  20Cos60i  + 20Sin60j

= 10i + 10√3j

F₁ + F₂ = 10i + 10i + 10√3j

= 20i + 10√3j

=> Tan alpha = 10√3/20

=> Tan alpha = √3/2