F1 =10N, F2 =20N and F3=20N with 60° and radius of the circle is 10m what is the net torque
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Explanation:
total force= F1+F2+F3
=10N+20N+20N
=50N
radius r=10m
so torque=total force×radius
= 50N×10m
= 500Nm
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