Question

F20 soft polynomial x cube minus 4 x square - 3 x + 12 is under root 5 and minus under root 5 then find its third zeros or root

Answer 1

Step-by-step explanation:

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Answer 2

Answer:

p (x)=x^3 - 4x^2 - 3x + 12

Step-by-step explanation:

It is given that the two zeroes of the polynomial p (x) are:

alpha = root 5 & beta = - root 5

Sum of its zeroes,

$\alpha + \beta + \gamma = - b \div a$

$\sqrt{5} + ( - \sqrt{5} ) + \gamma = - ( - 4) \div 1 \\ \sqrt{5} - \sqrt{5} + \gamma = 4 \\ \gamma = 4$

Hence, it's third zero or root is 4.

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