Question

फाइंड द इक्वेशन ऑफ द सर्कल व्हिच पास थ्रू द पॉइंट 20, 3 19 कॉम 8 एंड 2 कोमा - 9 फाइंड इट्स रेडियस एंड सेंटर​

Answer 1

Answer:

h the first to comment on this device is not a problem with the following angles and

Answer 2

Step-by-step explanation:

Given line equation be 2x−y=3

Points (3,−2),(−2,0)

Let (x

1

,y

1

) be centre ⇒2x

1

−y

1

=3...(1)

distance from points = radius [ Radius should be equal]

(x,−3)

2

+(y

1

+2)

2

=

(x+2)

2

+(y+o)

2

⇒x

2

+9−6x

1

+y

1

2

+4+4y

1

=x

1

2

+4+4x

1

+y

2

⇒10x

1

−4y

1

−9=0...(2)

solving 1 & 2

⇒10x

1

−4y

1

−9y−12=−8x

1

−4y−12=0

=2x

1

+3=0⇒x

1

=

2

−3

center =(−

2

3

,6)

Radius =

(3+

2

3

)

2

+(−2−6)

2

=

(

2

9

)

2

+64

=

4

337

Circular equation is:

(x+

2

3

)

2

+(y−6)

2

=

4

337

A