फाइंड द कॉस्ट ऑफ फेंसिंग और ए ट्रायंगुलर फील्ड ऑफ लेंथ 322 मीटर एंड ब्रेथ टू 80 मीटर एट द रेट ऑफ रुपीस 32 पॉइंट 50 मीटर
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Step-by-step explanation:
ANSWER
Dimension of triangle field ⇒120m,80m,50m
⇒ perimeter = 120 + 80 + 50
=250m
Area =
125(125−120)(125−80)125−50
=
125×5×45×75
=
25×5×5×9×5×5×15
=5×5×3×5
15
=375
15
=375(3.88)
=1455m
2
cost of fencing = 250−3
[perimeter of Remaining fence] = 247
Total cost ⇒247m×Rs20/m
=Rs4940.
as the rate are reduced by 25 %
∴ new lets is [20−20×
100
25
]⇒20−5=15%
Rs[4950−4950×
100
25
]
⇒4950(1−
4
1
)
4950×
4
3
Final cost ⇒Rs3712.5
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