Question

फाइंड द लार्जेस्ट नंबर विच डिवाइड्स 630 and 940 लिविंग रिमाइंडर 6 एंड 4 रिस्पेक्टिवली​

Answer 1

Since on dividing 630 by the required number, the remainder is 6. Therefore, 630−6=624 will be exactly divisible by the required number.

Similarly, 940−4=936 will be also exactly divisible by the required number.

Therefore, the required number is the HCF of 624 and 936.

Let us do the prime factorization of 624 and 936 to find the HCF:

624=2×2×2×2×3×13

936=2×2×2×3×3×13

⇒HCF(630,940)=2×2×2×3×13=312

Hence, 312 is the largest number which divides 630 and 940 leaving remainders 6 and 4.

Answer 2

312

312 divides 630 with remainder 6.

312 divides 940 with remainder 4.

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