Question

फाइंड द प्रोबेबिलिटी दैट ए लीप ईयर सिलेक्टेड अट रेंडम hai53 संडे।
find the probability that a leap year selected at random has 53 sundays.​

Answer 1

The two odd days can be

(Sunday,Monday),

(Monday,Tuesday},

(Tuesday,Wednesday),

(Wednesday,Thursday),

(Thursday,Friday),

(Friday,Saturday),

(Saturday,Sunday)

So there are 7 possibilities out of which 2 have a Sunday. So the probability of 53 Sundays in a leap year is

$\tt \: \frac{2}{7}$

HOPE IT HELPS✌