English, asked by kshitijdandriyal, 8 months ago

फाइंड द सब्जेक्ट एंड प्रिडिकेट इन दिस सेंटेंस द ट्रैप द लॉयन इन हिस नेट​

Answers

Answered by Simrankaur1025
3

Explanation:

\begin{gathered}\Large\bf{\color{peru}GiVeN,} \\ \end{gathered}

GiVeN,

A force of \bf{(5\hat{i}\:+\:4\hat{j})\:N}(5

i

^

+4

j

^

)N displaces a particle through \bf{(3\hat{i}\:-\:3\hat{j})\:m}(3

i

^

−3

j

^

)m .

\begin{gathered}\longmapsto\:\:\bf\blue{Force\:(F)\:=\:(5\hat{i}\:+\:4\hat{j})\:N} \\ \end{gathered}

⟼Force(F)=(5

i

^

+4

j

^

)N

\begin{gathered}\longmapsto\:\:\bf{\color{lime}Displacement\:(s)\:=\:(3\hat{i}\:-\:3\hat{j})\:m} \\ \end{gathered}

⟼Displacement(s)=(3

i

^

−3

j

^

)m

Power (P) = 0.6 W

\begin{gathered}\bf{\color{indigo}We\:know\:that,} \\ \end{gathered}

Weknowthat,

\begin{gathered}\red\bigstar\:\:{\pink{\boxed{\boxed{\bf{\color{cyan}Work\:done\:=\:F\:.\:s\:}}}}}---(i) \\ \end{gathered}

Workdone=F.s

−−−(i)

\begin{gathered}\Large\bf\orange{Or} \\ \end{gathered}

Or

\begin{gathered}\purple\bigstar\:\:{\green{\boxed{\boxed{\bf{\color{olive}Work\:done\:=\:Power\times{time}\:}}}}}--(ii) \\ \end{gathered}

Workdone=Power×time

−−(ii)

\begin{gathered}\bf\red{From\:equ^n(i)\:\&\:(ii)\:we\:get,} \\ \end{gathered}

Fromequ

n

(i)&(ii)weget,

\begin{gathered}:\implies\:\:\bf{F\:.\:s\:=\:Power\times{time}\:} \\ \end{gathered}

:⟹F.s=Power×time

\begin{gathered}:\implies\:\:\bf{Time\:=\:\dfrac{F\:.\:s}{Power}\:} \\ \end{gathered}

:⟹Time=

Power

)

\begin{gathered}:\implies\:\:\bf{Time\:=\:\dfrac{15\:(\hat{i}.\hat{i}\:+\:12\:(\hat{j}.\hat{i})\:-\:15\:(\hat{i}.\hat{j})\:-\:12\:(\hat{j}.\hat{j})}{0.6}\:} \\ \end{gathered}

:⟹Time=

0.6

15(

i

^

.

i

^

+12(

j

^

.

i

^

)−15(

i

^

.

j

^

)−12(

j

^

.

j

^

)

\begin{gathered}:\implies\:\:\bf{Time\:=\:\dfrac{15\times{1}\:+\:12\times{0}\:-\:15\times{0}\:-\:12\times{1}}{0.6}\:} \\ \end{gathered}

:⟹Time=

0.6

15×1+12×0−15×0−12×1

\begin{gathered}:\implies\:\:\bf{Time\:=\:\dfrac{15\:-\:12}{0.6}\:} \\ \end{gathered}

:⟹Time=

0.6

15−12

\begin{gathered}:\implies\:\:\bf{Time\:=\:\dfrac{3}{0.6}\:} \\ \end{gathered}

:⟹Time=

0.6

3

\begin{gathered}:\implies\:\:\bf{Time\:=\:\dfrac{30}{6}\:} \\ \end{gathered}

:⟹Time=

6

30

\begin{gathered}:\implies\:\:\bf\purple{Time\:=\:5\:s\:} \\ \end{gathered}

:⟹Time=5s

\Large\bold\therefore∴ The time of action is 5 seconds.

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