Question

फाइंड द सम ऑफ द नंबर इन बिटवीन100 to 200​

Answer 1

Step-by-step explanation:

Number between 100−200 divisible by 9 are 108,117,126,...198

Here, a=108.d=117−108=9 and a

n

=198

=a+(n−1)d=198

→ 108+(n−1)9=198

→ 9[12+n−1]=198⇒ n=22−11⇒ n=11

Now, S

n

=

2

n

[2a+(n−1)d]

⇒ S

11

=

2

11

[2(108)+(11−1)(9)]

=

2

11

[216+90]

=

2

11

×306

=11×153

⇒ S

11

=1683

(ii) Numbers between 100 and 200=101,102,103,....199

Here, a=101,d=1,a

n

=199

⇒ a+(n−1)d=199

⇒ 101+(n−1)(1)=199

⇒ (n−1)=199−101=98

⇒ n=99

Now, S

99

=

2

99

[2×101+(99−1)(1)]

=

2

99

[202+98]=

2

99

×300=99×150=14850

So, the sum of integers between 100 and 200 which are not divisible by 9=14850−1683=13167

Answer 2

Answer:

14850 is the correct answer

.

.

how are you sis