Question

Fabina borrows 12,500 at 12% per annum for 3 years at simple interest and

Radha borrows the same amount for the same time period at 10% per annum,

compounded annually. Who pays more interest and by how much?​

Answer 1

First we need to find Fabina's interest.

Simple Interest = PRT/100 = 12500*12*3/100 = 125*36 = Rs.4500

Interest = Rs.4500

Radha's amt = P*(1+r/100)raised to the power n

                         12500*(1+10/100) to the power 3 = 12500*11/10*11/10*11/10

                                                                                = 25*11*11*11/2 = Rs.16637.5

Radha's interest = Rs.16637.5 - Rs.12500 = Rs 4137.5

Radha has to pay less than Fabina.

Difference = 4500-4137= Rs. 363.

Fabina has to pay more than Radha by Rs.363

This is the answer.

Hope you have a great day! :)

Answer 2

Question :-

Fabina borrows ₹ 12,500 at 12% per annum for 3 years at simple interest and Radha borrows the same amount for the same time period at 10% per annum, compounded annually. Who pays more interest and by how much?

Given :-

Fabina borrows ₹ 12,500 at 12% per annum for 3 years at simple interest and Radha borrows the same amount for the same time period at 10% per annum, compounded annually.

Find Out :-

Who pays more interest and by how much?

Solution :-

Let fabina pays x amount of interest and radha pays y amount of interest .

Now , we will see the amount paid by both after 3 years.

For finding amount paid by Fabina -

P = Rs. 12,500

N = 3 years.

R = 12%

✭ $\bf SI = \dfrac{P×R×N}{100}$ ✭

➙ $\sf SI =\: \dfrac{12500 \times 3 \times 12}{100}$

➙ $\sf SI = \: 125 \times 3 \times 12$

$\implies$ ${\small{\bold{\purple{\underline{SI =\: Rs \: 4500}}}}}$

For finding amount paid by Radha -

P = Rs. 12500

N = 3 years.

R = 10% which is compounded annually.

✭ $\bf A = \: P\bigg(1 + \dfrac{r}{100} \bigg)^{n}$ ✭

➙ $\sf A = \: 12500\bigg(1 + \dfrac{10}{100} \bigg) {}^{3}$

➙ $\sf A = \: 12500\bigg( \dfrac{11}{10} \bigg) {}^{3}$

➙ $\sf A = \: 12500 \times \dfrac{11}{10} \times \dfrac{11}{10} \times \dfrac{11}{10}$

➙ $\sf A = \dfrac{125 \times 11 \times 11 \times 11}{10}$

$\implies$ ${\small{\bold{\purple{\underline{A =\: Rs \: 16637.5}}}}}$

∴ CI = Rs. 16637.5 - 12500

➙ Rs. 4137. 50

Therefore , amount paid by radha = Rs. 4137.50

So , difference of money

➙ Rs. 4500 - Rs. 4137.50

➙ Rs. 362.5

Henceforth, Fabina pays Rs. 362.5 more.

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