Math, asked by william98, 1 year ago

FABINA BORROWS 12500 AT 12% P. A FOR 3YEARS AT SIMPLE INTEREST AND RADHA BORROWS THE SAME AMOUNT FOR THE SAME TIME PERIOD AT 10% P. A COMPOUNDED ANNUALLY WHO PAYS MORE INTEREST AND BY HOW MUCH

Answers

Answered by 27jenny
4
HEYYY MATE....
THANKS FOR THE QUESTION...
UR ANS IS HERE IN THE ATTACHMENT....
HOPE IT HELPS U...
IF IT IS HELPFUL TO YOU PLZZZ MARK ME BRAINLIEST ......
BE FREE 4 ASKING DOUBT...
Attachments:
Answered by Anonymous
0

Given:

→ Fabiana borrows ₹ 12,500 at 12% per annum for 3 years at simple interest and Radha borrows the same amount for the same time period at 10% per annum, compounded annually.

Find:

→ Who pays more interest and by how much?

Using formula:

→ S.I = (Principal × Rate × Time)/100

→ A = Principal (1 + Rate/100)ⁿ

→ C.I = Amount - Principal

Note:

→ (ⁿ) = Number of years or Time period.

Calculations:

★ Finding for Radha:

→ (12500 × 12 × 3)/100

→ 450000/100

→ 4500

★ Finding for Fabina:

→ 12500 × (1 + 10/100)³

→ 12500 × (11/10)³

→ {12500 (11 × 11 × 11)}/1000

→ 125 × 1331/10

→ 166375/10

→ 16637.5

★ Amount paid by Radha:

→ 16637.50 - 12500

→ 4137.5

★ Fabia pays more:

→ 4500 - 4137.50

→ 362.5

Hence, Fabia pays more 362.5 than Radha.

Similar questions