Math, asked by asha8049, 3 months ago

Fabina borrows ₹ 25000 at 15% per annually for 2 years at simple interest and Radha borrowed the same amount for the same time provide and same rate but compounded annually who plays more interest and by how much?​

Answers

Answered by Anonymous
1

Fabina borrows ₹ 25000 at 15% per annually for 2 years at simple interest and Radha borrowed the same amount for the same time provide and same rate but compounded annually.

Here, Principal = ₹ 25000

Rate of interest = 15% per annum

Time = 2 years

Therefore, simple interest of Fabina

 =₹( \frac{25000 \times 15 \times 2}{100})  \\  = ₹7500

Therefore, compound interest of Radha

 = ₹25000(1 +  \frac{15}{100})^{2} - ₹25000 \\  = ₹(25000 \times  \frac{23}{20}  \times  \frac{23}{20}  - 25000) \\  = ₹(33062.50 - 25000) \\  = ₹8062.50

Therefore, we can clearly see that the interest of Radha is more than that of Fabina.

Therefore, difference between the two interests

 = ₹(8062.50 - 7500) \\  = ₹562.50

Answer:

Radha pays more interest by ₹562.50

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