face center cubic unit cell element (atomic mass=60)and cell edge 400pm.what is the density of unit cell?
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its fcc so z= 4 , M=60 ,a=400 so its density is d=z.m/Na . a^3
d= (4 x 60)/(400)^3 x 6.022x 10^23
d= (4 x 60)/(400)^3 x 6.022x 10^23
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