Question

facforise:
${x}^{8 } - 1$

Answer 1

x^8-1

=(x^4)^2-1

=(x^4-1)(x^4+1)

=(x^2-1)(x^2+1)(x^4+1)

=(x+1)(x-1)(x^2+1)(x^4+1)

Hope it helps

Answer 2

Hi.

$x^8 - 1\\\\= (x^4)^2 - 1^2\\\\= (x^4+1)(x^4 -1)\\\\= (x^4+1)((x^2)^2 - 1^2)\\\\= (x^4+1)(x^2+1)(x^2 - 1)\\\\= (x^4+1)(x^2+1)(x^2 - 1^2)\\\\= \boxed{(x^4+1)(x^2+1)(x+1)(x-1)}$

Hope it helps.