facktorize a6+32a3-64
Answers
Answered by
42
⭐⭐⭐⭐⭐ ANSWER ⭐⭐⭐⭐⭐
❄ FACTORISATION ❄
The process of finding two or more algebric expressions whose product is the given expression is called factorisation.
❄ SIMPLE EXAMPLE ❄
4x²-25
= (2x)²-(5)²
= (2x+5) (2x-5) [Ans.]
❄ FORMULA TO BE USED HERE ❄
a³+b³+c³-3abc = (a+b+c) (a²+b²+c²-ab-bc-ca)
❄ SOLUTION ❄
[tex] {a}^{6} + {32a}^{3} - 64
= (a²)³+(-4)³+(2a)³-3×a²×(-4)×(2a)
= (a²-4+2a) (a⁴+16+4a²+4a²+8a-2a³)
= (a²+2a-4) (a⁴+16+8a²+8a-2a³)
= (a²+2a-4) (a⁴-2a³+8a²+8a+16) [Ans.]
⭐⭐⭐ ALWAYS BE BRAINLY ⭐⭐⭐
❄ FACTORISATION ❄
The process of finding two or more algebric expressions whose product is the given expression is called factorisation.
❄ SIMPLE EXAMPLE ❄
4x²-25
= (2x)²-(5)²
= (2x+5) (2x-5) [Ans.]
❄ FORMULA TO BE USED HERE ❄
a³+b³+c³-3abc = (a+b+c) (a²+b²+c²-ab-bc-ca)
❄ SOLUTION ❄
[tex] {a}^{6} + {32a}^{3} - 64
= (a²)³+(-4)³+(2a)³-3×a²×(-4)×(2a)
= (a²-4+2a) (a⁴+16+4a²+4a²+8a-2a³)
= (a²+2a-4) (a⁴+16+8a²+8a-2a³)
= (a²+2a-4) (a⁴-2a³+8a²+8a+16) [Ans.]
⭐⭐⭐ ALWAYS BE BRAINLY ⭐⭐⭐
Similar questions