facotrize the following
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(i) The polynomial is
(x²–x)² -8(x²-x)+12
y=(x²-x)
Then the polynomial becomes
y²-8y+12
=y²-6y-2y+12
y(y-6) -2(y-6)
=(y-2) (y-6)
=(x²-x-2) (x²-x-6)
Now both the factors can be further factorized
(x²-2x+x-2) (x²-3x+2x-6)
{(x-2) + 1(x-2)} {x(x-3) + 2(x-3)}
=( x+1) (x-2) (x+2) (x-3) is the correct answer
Hope you understood!
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