Math, asked by Anonymous, 9 months ago

Factor: 16w3 – u4w3???????????????????????/

Answers

Answered by Anonymous
1

\huge\boxed{\fcolorbox{cyan}{grey}{Sulution.!!!:-}}.

Given here:-.

Factors is, 16w³-u⁴w³

= 16w³-u⁴w³.

16w³-u⁴w³.= w³(16-u⁴).

16w³-u⁴w³.= w³(16-u⁴).= w³[4²-(u²)²].

16w³-u⁴w³.= w³(16-u⁴).= w³[4²-(u²)²].=w²[4+u²][4-u²].

16w³-u⁴w³.= w³(16-u⁴).= w³[4²-(u²)²].=w²[4+u²][4-u²].=w³(4+u²(2+u)(2-u).

Hopes its helpa u.

Answered by Anonymous
14

Answer:

Answer: w^3(4 + u^2)(2 + u)(2 - u).

Step-by-step explanation:

=16w^3 – u^4w^3.

= w^3(16 – u^4).

= w^3(42 - ((u^2)^2).

= w^3(4 + u^2)(4 - u^2).

= w^3(4 + u^2)(22 - u^2).

= w^3(4 + u^2)(2 + u)(2 - u).

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