Question

Factor 3x³ - x²y +6x²y - 2xy² + 3xy2²- y³ =

(3x - 2y)(x + y)

(3x - y)(x + y)(x - y)

(3x - y)(x + y)²

(3x - y)(x² + y²)

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Answer 1

Answer:

OPTION C IS CORRECT.

Step-by-step explanation:

$3 {x}^{3} - {x}^{2} y + 6 {x}^{2} y - 2x {y}^{2} + 3x {y}^{2} - {y}^{3} = {x}^{2} (3 {x}^{} - y {)}^{} + 2x {y}^{} (3x - y) + {y}^{2} (3x - y) \\ \\ = (3x - y)( {x}^{2} + 2xy + { {y}^{2} ) }^{} \\ \\ = (3x - y) {(x + y)}^{2} \\ \\ \\ option \: c \: is \: correct.$