Question

Factor and hence factorise

Answer 1

${6x}^{3} + 13 {x}^{2} - 4$

${6x}^{3} - 3x {}^{2} + 16x {}^{2} - 8x + 8x - 4$

$(2x - 1)(3 {x}^{2} + 8x + 4)$

$(2x + 1)( {3x}^{2} + 6x + 2x + 4)$

$(2x - 1)(3x(x + 2) + 2(x + 2))$

$(2x - 1)(x + 2)(3x + 2)$

hope it helps you.........

Answer 2

Hey mate

here is your answer

Hope this helps you

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