Question

Factor by grouping.
4u^3+5u^2+28u+35

Answer 1

Answer:

4u3-5u2-28u+35

Final result :

(4u - 5) • (u2 - 7)

Step by step solution :

Step 1 :

Equation at the end of step 1 :

(((4 • (u3)) - 5u2) - 28u) + 35

Step 2 :

Equation at the end of step 2 :

((22u3 - 5u2) - 28u) + 35

Step 3 :

Checking for a perfect cube :

3.1 4u3-5u2-28u+35 is not a perfect cube

Trying to factor by pulling out :

3.2 Factoring: 4u3-5u2-28u+35

Thoughtfully split the expression at hand into groups, each group having two terms :

Group 1: -5u2+35

Group 2: 4u3-28u

Pull out from each group separately :

Group 1: (u2-7) • (-5)

Group 2: (u2-7) • (4u)

-------------------

Add up the two groups :

(u2-7) • (4u-5)

ℍ⌾ℙℰ ⅈᝨ ℳᗅℽ ℍℰℒℙ Ⴎ

ℙℒℰᗅՏℰ ℳᗅℛK ⅈᝨ ᗅՏ ᗅ ℬℛᗅⅈℕℒⅈՏᝨ ᗅℕՏᗯℰℛ

Answer 2

Answer:

(u^2+7) (4u+5)

Step-by-step explanation:

4u^3+5u^2+28u+35

now taking out common simply

u^2(4u+5) +7 ( 4u+5)

(u^2+7) (4u+5)