Question

Factor completely!!! 4y2 + 25y + 6

Answer 1

✔4y² + 25y + 6

➬4y² + (24+1)y + 6

➬4y² + 24y + y + 6

➬4y (y + 6) + 1 (y + 6)

➬(y + 6) (4y + 1)

✔y + 6 = 0 and 4y + 1 = 0

y = -6 and y = -1/4 (ans).

ʜᴏᴘᴇ ɪᴛ ʜᴇʟᴘs ʏᴏᴜ

❤ᴛʜᴀɴᴋ ʏᴏᴜ❤

Answer 2

Answer:

$4 {y}^{2} + 25y + 6 = 0 \\ \\ = > 4 {y}^{2} + 24y + y + 6 = 0 \\ \\ = > 4y(y + 6) + 1(y + 6) = 0 \\ \\ = > (4y + 1)(y + 6) = 0$

IT IS A QUADRATIC EQUATION SO MAXIMUM VALUE OF GIVEN VARIABLE OR MAXIMUM ROOT OR SOLUTION CAN BE 2.

SO VALUE OF ARE:

$4y + 1 = 0 \\ \\ = > y = \frac{ - 1}{4} \\ \\ \\ \\ \\ y + 6 = 0 \\ \\ = > y = - 6$