factor completely 8r3-64r2+r-8
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3
Answer:
Answer:
(
8
r
2
+
1
)
(
r
−
8
)
Explanation:
In grouping, separate the first two terms (in this case,
8
r
3
and
−
64
r
2
) from the second two terms (in this case,
r
and
−
8
):
(
8
r
3
−
64
r
2
)
+
(
r
−
8
)
→
Factor out the GCF from each of the pairs in the parentheses
8
r
2
(
r
−
8
)
+
1
(
r
−
8
)
→
Combine the
8
r
2
and
1
(
8
r
2
+
1
)
(
r
−
8
)
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