Question

Factor completely of 64 - p6​

Answer 1

Answer:

(8)²-(p³)²

=(8+p³)(8-p³)

=(8+p³){(2)³-(p)³}

=(8+p³)(2-p){(2)²+2.p+(p)²}

=(8+p³)(2-p)(4+2p+p²)

Answer 2

Given :  64 - p⁶

To Find :  Factorize

Solution:

64 - p⁶

= 8²  -(p³)²

using a² - b² = (a + b)(a - b)

= ( 8 + p³)(8 - p³)

= ( 2³ + p³)(2³ - p³)

a³ - b³ = (a- b)(a²+ ab + b²)

a³ + b³ = (a + b)(a² - ab + b²)

= (2 + p)(p² -2p + 4) (2 - p)(p² + 2p + 4)

64 - p⁶  = (2 + p)(p² -2p + 4) (2 - p)(p² + 2p + 4)

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