Question

Factor each Fully

$18x^{2} -48x+32$

Answer 1

$\blue{\boxed{\huge{\red{\boxed {\green{\mathfrak{ANSWER}}}}}}}$

$\orange{\underline{\huge</p><p>{\bold{\textit{\green{\bf{Factorize}}}}}}}$

$18 {x}^{2} - 48x + 32 = 0$

Divide 2 on both side.

$9 {x}^{2} - 24 + 16 = 0$

$9 {x}^{2} - 12x - 12x + 16 = 0 \\ 3x(3x - 4) - 4(3x - 4) = 0 \\ (3x - 4)(3x - 4) = 0 \\ \\ 3x - 4 = 0 \:\: and \:\: 3x-4=0 \\ x = \frac{4}{3} \: \: and \: \: x = \frac{4}{3}$

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Answer 2

Answer:

The answer is $=2\left(3x-4\right)^2$

Step-by-step explanation:

$18x^2-48x+32$

$=2* \:9x^2-2* \:24x+2*\:16$

$=2\left(9x^2-24x+16\right)$

$9x^2-24x+16=\quad \left(3x-4\right)\left(3x-4\right)$

$=2\left(3x-4\right)\left(3x-4\right)$

$=2\left(3x-4\right)^2$