Question

factor of 4y^2-4y+1 is​

Answer 1

Answer:

4y²-4y+1 = (2y-1)(2y- 1). Explanation: Method 1: Given quadratic expression: 4y²-4y+1. = (2y)²-2×2y×1+1². =(2y- 1) ...

Answer 2

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4y²‐4y+1 = (2y)²-2(2y)(1)+1²

Using identity 2

= (2y-1)²=(2y-1)(2y-1)

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