Math, asked by Dnyaneshwari575, 8 months ago

factor of 6x^2-7x-3? please it's urgent​

Answers

Answered by Kausmitachakrabarti
1

Answer:

Factor: y=6x2+7x−3

Ans: (3x + 1)(2x - 3)

Explanation:

Use the new AC Method. y = 6(x - p)(x - q)

Converted trinomial: y'=x2+7x−18 = (x - p)(x - q)

p' and q' have opposite signs (Rule of signs).

Factor pairs of 18 --> (-1. 18)(-2, 9). This sum is 7 = -b.

Then p' = 2 and q' = -9.

Therefor, p=(p'a)=26=13 and q'=−96=−32

y = 6(x + 1/3)(2x + 3) = (3x + 1)(2x - 3)

Step-by-step explanation:

Hope it help you

Answered by Anonymous
1

Answer:

(3x+1)(2x-3)

Step-by-step explanation:

6x^{2} - 7x + 3

= 6x^{2} - (9-2)x + 3

= 6x^{2} -9x + 2x - 3

= 3x(2x-3) + 1(2x-3)

= (3x+1)(2x-3)

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