Question

factor of p3+1/p3+26/27​

Answer 1

Answer:

(p + 1/p - 1/3)(p² + 1/p² - 8/9  +1/3p  + p/3)

Step-by-step explanation:

p^3+1/p^3+26/27 solve the factorization

p³ + 1/p³ + 26/27

= p³ + 1/p³ -1/27  + 1

= p³ + 1/p³ + (-1/3)³  - 3* p (1/p)(-1/3)

using identity

a³+ b³ + c³ - 3abc = (a + b + c) (a² + b² + c² - ab - bc - ca)

a = p  b = 1/p  c = -1/3

= (p + 1/p - 1/3)(p² + 1/p² + 1/9  - 1  +1/3p  + p/3)

= (p + 1/p - 1/3)(p² + 1/p² - 8/9  +1/3p  + p/3)

I hope my answer helps you. Please mark me as the brainliest.