factor of x^2+y-xy-x
Answers
Answered by
522
Hey !!!
x² + y - xy - x
x² - x - yx + y {just Rearranging term }
x( x - 1 ) - y ( x - 1 )
(x - y ) ( x - 1 ) factorised here !!
________________________
Hope it helps you !!!.
@Rajukumar111
x² + y - xy - x
x² - x - yx + y {just Rearranging term }
x( x - 1 ) - y ( x - 1 )
(x - y ) ( x - 1 ) factorised here !!
________________________
Hope it helps you !!!.
@Rajukumar111
Answered by
12
Given,
Polynomial: x² + y - xy - x.
To find,
Factors of the given polynomial.
Solution,
Let the given polynomial be represented by p(x). That is,
p(x) = x² + y - xy - x.
Now, the factors of the polynomial p(x) can be found using factorization, as follows.
Rearranging p(x),
p(x) = x² - xy - x + y
Now, simplifying, or factorizing the above expression, we get,
p(x) = x(x - y) - (x - y)
⇒ p(x) = (x - 1)(x - y)
⇒ Factors of p(x) = (x - 1) and (x - y).
Therefore, the factors of x² + y - xy - x, will be (x - 1) and (x - y).
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