factor of x²-(a+1/a)x+1
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Step-by-step explanation:
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Step-by-step explanation:
Given:
\bf\:x^2-(a+\frac{1}{a})x+1x
2
−(a+
a
1
)x+1
x^2-(a+\frac{1}{a})x+1x
2
−(a+
a
1
)x+1
=x^2-ax-\frac{1}{a}x+1=x
2
−ax−
a
1
x+1
=x(x-a)-\frac{1}{a}(x-a)=x(x−a)−
a
1
(x−a)
=(x-\frac{1}{a})(x-a)=(x−
a
1
)(x−a)
\implies\bf\:x^2-(a+\frac{1}{a})x+1=(x-\frac{1}{a})(x-a)⟹x
2
−(a+
a
1
)x+1=(x−
a
1
)(x−a)
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