Question

Factor the expression (a -2b -3c)square

Answer 1

( a- 2b - 3c ) ^2
Identity = ( a+b+c)^2
= a^2 +b^2+c^2+2ab+2bc+2ca
So,
= (a)^2+(-2b)^2+
(-3c)^2+2×a×-2b+2×-2b×-3c+2×-3c×a
= a^2+4b^2+9c^2+(-4ba)+(12bc)+(-6ca)
= a^2+4b^2+9c^2-4ba+12bc-6ca

That's the correct answer .

Answer 2

Heya ✋

Let see your answer !!!!!


$(a - 2b - 3c) ^{2} \\ = (a) ^{2} + ( - 2b) ^{2} + ( - 3c) ^{2} + \\ 2 \times a \times ( - 2b) + 2 \times ( - 2b) \times \\ ( - 3c) + 2 \times ( - 3c) \times a \\ = a ^{2} + 4b ^{2} + 9c ^{2} - 4ab + \\ 12bc - 6ca$





Thanks :))))