Question

Factor the following polynomials. brainlist for those correct x^9y^3 − 8z^6

Answer 1

Factor x9y3−8z6

x9y3−8z6

=(x3y−2z2)(x6y2+2x3yz2+4z4)

Answer:

(x3y−2z2)(x6y2+2x3yz2+4z4)

Answer 2

Step-by-step explanation:

factoring . x^9y^3-8z^6

THEORY:a difference of two perfect cubes, a^3-b^ 3e factored into (a-b) ×(a^2+ab+b^2)

PROOF: (a-b)×(a^2+ab+b^2)a^3+a^2b+ab^2-ba^2-b^2a-b^3=

a^3+(a^2b-ba^2)+(ab^2-b^2a)-b^3=

a^3+0+0+b^3

a^3+b^3.

CHECK:8is the cube of 2

CHECK:x^9is the cube of x^3

CHECK:y cube is the cube of y^1

CHECK:z^6is the cube of z^2.

FACTORIZATION :(x^3-2z^2)×(x^6y^2+2x^3yz^2+4z^4)

FACTORING:

x^3y-2z^2)

CHECK:2 is not a cube !!

Ruling: binomial cannot be factored as the difference of two perfect cubes.

Factoring:x^6y^2+2x^3yz^2+4z^4try to factor this multi variable trinomial using trial and error.

Factorization fails.

so factorization of polynomial x^9y^3-8x^6 is(x^3y-2z^2)×(x^6y^2+2x^3yz^2+4z^4). make it brainlist .