Factor the
given expressions using identity
(x+y)^2 = x² + y² + 2xy
(x-y)² = x² + y² - 2xy
x^2- y^2 = (x-y) (x+y)
(1) p² +6p+q
(2) 4z²- 4 z+ 1
(3) a^4 - 8a^2b^2 + 16 b^4)- 81
(4) 625 - x^2 - 2xy - y^2
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Answer:
1) p^2+2(p)(3q)+(3q)^2= (p+3q)^2
2)(2z)^2-2(2z)+1^2=(2z-1)^2
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