Factor this polynomial by grouping the terms. 2x−2y+dx−dy
A. (2x−2y)+(dx−dy)
B. (2x−2y)(dx−dy)
C. 2(x−y+dx−dy)
D. (2+d)(x−y)
Answers
Answered by
3
2x-2y+dx-dy=0
2(x-y)+d(x-y)=0
(2+d)(x-y)=0
Option D is your answer
Hope it's help you friend ☺️
2(x-y)+d(x-y)=0
(2+d)(x-y)=0
Option D is your answer
Hope it's help you friend ☺️
Answered by
4
D. (2+d)(x-y)
Why??
Because 2x-2y+dx-dy
= 2(x-y) + d(x-y)
= (2+d)(x-y)
this is the correct answer. Mark this as the brainliest answer if it meets your expectations!!
Why??
Because 2x-2y+dx-dy
= 2(x-y) + d(x-y)
= (2+d)(x-y)
this is the correct answer. Mark this as the brainliest answer if it meets your expectations!!
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