factor this sum of two squares, 4x² + 9y²
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Step-by-step explanation:First, expand the second part.
(2x-y)^2 = 4x^2 - 4xy + y^2
Subtract that from the first part (9y^2) so you get
8y^2 + 4xy - 4x^2
Then work on factoring
4(2y^2 + xy - x^2)
This is a + + -, therefor it will be a
(a+b)(c-b) factorial, and because the middle term is positive, c>a or cb>ab
I.e.
ac = 2y^2
bc - ac = xy
(b)(-b) = -x^2
From this, it easily becomes
(2y-x)(y+x) = 2y^2 + 2xy - xy -x^2 =
2y^2 + xy - x^2
Therefore this factors out to
(4)(2y-x)(y+x
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