Question

Factor to find the zeros of the function: y = 8x2 + 8x − 96


A) x = 4 or x = 3
B) x = −4 or x = 3
C) x = 4 or x = −3
D) x = −4 or x = −3

Answer 1

put the given value of x in the in the given equation

Answer 2

The factors are $\bold{x=3 \text { or } x=-4}$

Given:

$y=8 x^{2}+8 x-96$

To find:

The factors of the given equation.

Solution:

$8 x^{2}+8 x-96=0$

Now, divide the entire quadratic equation by 8, we get

$x^{2}+x-12=0$

Now, to find the factors of the given equation, factorize the above quadratic equation, we get

$\begin{array}{c}{x^{2}+4 x-3 x-12=0} \\ {x(x+4)-3(x+4)=0} \\ {(x-3)(x+4)=0}\end{array}$

Now, equating the above factors to zero, we get

$\begin{array}{l}{x-3=0, x+4=0} \\ {\Rightarrow x=3, x=-4}\end{array}$

Hence, the factors are $x=3 \text { or } x=-4$