Question

Factor to find the zeros of the function: y = 8x2 + 8x − 96
A) x = 4 or x = 3
B) x = −4 or x = 3
C) x = 4 or x = −3
D) x = −4 or x = −3

Answer 1

so 2 zeroes are 3,-4

Answer 2

The required option is B) x = - 4 or 3.

Step-by-step explanation:

We have,

$y = 8x^2+8x-96$

To find, the zeros of the functions = ?

∴ $8x^2+8x-96=0$

Dividing both sides by 8, we get

$x^2+x-12=0$

⇒ $x^2+4x-3x-12=0$

⇒ $x(x+4)-3(x+4)=0$

⇒ $(x+4)(x-3)=0$

⇒ $x+4=0$ or, $x-3=0$

∴ x = - 4 or 3

Hence, the required option is B) x = - 4 or 3.