factor use 27y³+125x³
Answers
Answered by
46
we can use
x³+y³=(x+y)(x²-xy+y²)
27y³+125z³
(3y)³+(5z)³
(3y+5z)((3y)²-3yX5z+(5x)²)
(3y+5z)(9y²-15yz+25x²)
x³+y³=(x+y)(x²-xy+y²)
27y³+125z³
(3y)³+(5z)³
(3y+5z)((3y)²-3yX5z+(5x)²)
(3y+5z)(9y²-15yz+25x²)
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Answered by
27
27y³ + 125x³
[ we can express 27as 3³ and 125 as 5³]
or, (3y)³+(5x)³
[ Use identity x³+y³ = (x+y)(x²-xy+y²) ]
or, (3y+5x)((3y)²-(3y)(5x)+(5x)²)
or, (3y+5x)(9y² - 15xy + 25x²)
_____________________________
[ we can express 27as 3³ and 125 as 5³]
or, (3y)³+(5x)³
[ Use identity x³+y³ = (x+y)(x²-xy+y²) ]
or, (3y+5x)((3y)²-(3y)(5x)+(5x)²)
or, (3y+5x)(9y² - 15xy + 25x²)
_____________________________
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