Factor x3 + 3x2 + 2x completely. x(x2 + 3x + 2) x(x + 1)(x + 2) x(x – 1)(x – 2)
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FIRST TAKE COMMON AS X
x[x²+3x+2]
x[x²+2x+1x+2]
x[x(x+2)+1(x+2)]
x[x+1] [x+2]
x[x²+3x+2]
x[x²+2x+1x+2]
x[x(x+2)+1(x+2)]
x[x+1] [x+2]
Answered by
12
Answer:
2nd answer
Step-by-step explanation:
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