factor x³+3x²+7x+10 answer
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Answer:
(x+2)(x^2+x+5)
Step-by-step explanation:
First, find all factors of the constant term 10.
= 1,2,5,10
Substitute 1 into x. Since the result is not 0, x-1 is not a factor.
(1)^3+3(1)^2 + 7(1) +10 = 21
Substitute -1 into x. Since the result is not 0, x+1 is not a factor.
(-1)^3+3(-1)^2 + 7(-1) +10 = 5
Substitute 2 into x. Since the result is not 0, x-2 is not a factor.
(2)^3+3(2)^2 + 7(2) +10 = 44
Substitute -2 into x. Since the result is 0, x+2 is a factor.
(-2)^3+3(-2)^2 + 7(-2) +10 = 0
Now, we need to apply the polynomial division.
We need to divide x³+3x²+7x+10 by x+2
I've attached the division steps file below.
We need to rewrite the expression = x^2+x+5
So, the final answer would be (x+2)(x^2+x+5)
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