Factori 3x2 + 27y2 + z2 - 18xy + 6 √3yz -2 √3zx
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3x² + 27y² + z² - 18xy + 6 √3yz -2 √3zx
⇒ [-√3 x+3√3y+z]²
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Answer:
The identity here is (a+b+c)^2=a^2+b^2+c^2+2ab+2bc+2ca
Step-by-step explanation:
therefore (-x)^2+(3y)^2+z^2+2(-x)(3y)+2(3y)(z)+2(z)(-x)
=(-x+3y+z)^2
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