Question

factoriation:- a^2-64​

Answer 1

$a^{2}$ - 64

We know the square root for 64 that is 8

So,  

    $a^{2}$ - $8^{2}$

Using Identity,  

                           $a^{2}$ - $b^{2}$  =  ( a + b ) ( a - b )

                           $a^{2}$ - $8^{2}$    =  ( a + 8 ) ( a - 8 )

So, the factors of $a^{2}$ - 64 are ( a + 8 )  ( a - 8 )

Answer 2

Answer:

$a^2 - 64$ = (a - 8) (a + 8)

Step-by-step explanation:

Formula: $a^2 - b^2 = (a - b) (a + b)$

64 is a square of 8.

$a^2 - 64 \\= a^2 - 8^2$

= (a - 8) (a + 8)

So, $a^2 - 64$ = (a - 8) (a + 8)