Question

factorice 3ab+6bc+4ad+8cd​

Answer 1

$3ab + 6bc + 4ad + 8cd$

$3b(a + 2c) + 4d(a + 2c)$

$(a + 2c)(3b + 4d)$

hope it helps you....

Answer 2

Answer:

Split 3ab + 6bc + 4ad + 8cd

into two 2-term polynomials

+ 6bc + 3ab and + 4ad + 8cd

This partition did not result in a factorization. We'll try another one:

3ab + 6bc and + 4ad + 8cd

This partition looks good

1.2 Pull out from each binomial separately

3ab + 6bc = 3b • (a + 2c)

+ 4ad + 8cd = + 4d • (a + 2c)

1.3 Add up to arrive at the desired factorization

(3b + 4d) • (a + 2c)