Question

factorice : 49a² +70ab+25b
${b}^{2}$


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Answer 1

Step-by-step explanation:

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Answer 2

• Here you see that

$\pink \implies</strong></p><p><strong>\rm{49{a}^{2} = (7a) {}^{2}, \: 25 {b}^{2} = (5b) {}^{2}, 70ab = 2(7a)(5b)}$

Comparing the given expression with x²+2xy+y², we observe that x=7a and y=5b,

• Using identity I, we get

$\blue\implies\rm{49 {a}^{2} + 70ab + 25 {b}^{2} = (7a + 5b) {}^{2} =(7a + 5b)(7a + 5b) }$